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Old 07-08-2007, 05:52 AM
Don Bowey
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Default Re: AM electromagnetic waves: 20 KHz modulationfrequencyonanastronomically-low carrier frequency

On 7/7/07 9:17 PM, in article 469064fd$0$16540$4c368faf@roadrunner.com, "Ron
Baker, Pluralitas!" <this@aint.me> wrote:

>
> "Don Bowey" <dbowey@comcast.net> wrote in message
> news:C2B403C2.6DC94%dbowey@comcast.net...
>> On 7/4/07 8:42 PM, in article 468c6838$0$4664$4c368faf@roadrunner.com,
>> "Ron
>> Baker, Pluralitas!" <this@aint.me> wrote:
>>
>>>
>>> "Don Bowey" <dbowey@comcast.net> wrote in message
>>> news:C2B16AE5.6D5BC%dbowey@comcast.net...
>>>> On 7/4/07 10:16 AM, in article 468bd5ad$0$16531$4c368faf@roadrunner.com,
>>>> "Ron Baker, Pluralitas!" <this@aint.me> wrote:
>>>>
>>>>>
>>>>> "Don Bowey" <dbowey@comcast.net> wrote in message
>>>>> news:C2B1129D.6D573%dbowey@comcast.net...
>>>>>> On 7/4/07 7:52 AM, in article
>>>>>> 468bb3c0$0$24780$4c368faf@roadrunner.com,
>>>>>> "Ron
>>>>>> Baker, Pluralitas!" <this@aint.me> wrote:
>>>>>
>>>>> <snip>
>>>>>
>>>>>>>
>>>>>>> cos(a) * cos(b) = 0.5 * (cos[a+b] + cos[a-b])
>>>>>>>
>>>>>>> Basically: multiplying two sine waves is
>>>>>>> the same as adding the (half amplitude)
>>>>>>> sum and difference frequencies.
>>>>>>
>>>>>> No, they aren't the same at all, they only appear to be the same
>>>>>> before
>>>>>> they are examined. The two sidebands will not have the correct phase
>>>>>> relationship.
>>>>>
>>>>> What do you mean? What is the "correct"
>>>>> relationship?
>>>>>
>>>>>>
>>>>>> One could, temporarily, mistake the added combination for a full
>>>>>> carrier
>>>>>> with independent sidebands, however.
>>>>>>
>>>>>>
>>>>>>
>>>>>>>
>>>>>>> (For sines it is
>>>>>>> sin(a) * sin(b) = 0.5 * (cos[a-b]-cos[a+b])
>>>>>>> = 0.5 * (sin[a-b+90degrees] - sin[a+b+90degrees])
>>>>>>> = 0.5 * (sin[a-b+90degrees] + sin[a+b-90degrees])
>>>>>>> )
>>>>>>>
>>>>>>> --
>>>>>>> rb
>>>>>>>
>>>>>>
>>>>>
>>>>>
>>>>
>>>> When AM is correctly accomplished (a single voiceband signal is
>>>> modulated
>>>
>>> The questions I posed were not about AM. The
>>> subject could have been viewed as DSB but that
>>> wasn't the specific intent either.

>>
>> You should take some time to more carefully frame your questions.
>>
>> Do you understand that a DSB signal *is* AM?

>
> So all the AM broadcasters are wasting money by
> generating a carrier?



You are an ignorant, useless troll, and not worth my time


>
>>
>> Post your intention; it might help.
>>
>>>
>>>> onto a carrier via a non-linear process), at an envelope detector the
>>>> two
>>>> sidebands will be additive. But if you independe ntly place a carrier
>>>> at
>>>> frequency ( c ), another carrier at ( c-1 khz) and another carrier at
>>>> (c+
>>>> 1
>>>> kHz), the composite can look like an AM signal, but it is not, and only
>>>> by
>>>> the most extreme luck will the sidebands be additive at the detector.
>>>> They
>>>> would probably cycle between additive and subtractive since they have no
>>>> real relationship and were not the result of amplitude modulation.
>>>>
>>>
>>>

>>

>
>



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