On 24 Feb 2007 15:53:59 -0800, "jameshanley39@yahoo.co.uk"
<jameshanley39@yahoo.co.uk> wrote:

>On 24 Feb, 19:32, kony <s...@spam.com> wrote:
>> On 24 Feb 2007 10:53:56 -0800, "jameshanle...@yahoo.co.uk"
>>
>> <jameshanle...@yahoo.co.uk> wrote:
>> >On 23 Feb, 21:02, "Rod Speed" <rod.speed....@gmail.com> wrote:
>> >> So its a different number system.
>>
>> >No, 2^x cannot even be binary. The number 2 doesn't even exist in
>> >binary.
>>
>> The significant detail is that 1,000,000 being called
>> megabyte is invalid.
>>
>
>that's true but that's a different point to the one I made
>
>> Because byte only exists in a different system, not a
>> decimal system, the two different system terms can't be
>> intermixed.
>
>no.. Byte means 8 bits. But you can count bytes in any number system.

Not really, it is an invalid expression to have more than
one system mangled into a single quantity.


>And a Byte itself is nothing to do with a number system at all really.
>It's an "articificial" unit to count 8 binary digits. It's a concept.
>It doesn't really exist dependent or as part of a number system.

Wrong, it is just as real a part of a number system as any
other term, or if you want to call it a "concept", so is any
numerical term.

>> Similarly a
>> kilobyte is never 1000, and a byte itself is never 10 bits.
>>
>
>that parallel is absurd.

Nope, it would be equally absurd to put byte in front of a
decimal system value. Can't mix two systems in one
expression.